Good day everyone :)

Can i get a little help please?

I want to generate a doc file from a model and wanna show an image from an attribute which have an image url.

I have an object, which has a description attribute. 

This attribute contains an image url, which is :

My problem is, when i ran my code, it makes a system path from the url like this:


And the error message is : The filename, directory name, or volume label syntax is incorrect


I am running the following code below:


//----------------------------Read Image from Attribute----------------------------------


                //Path of the requested picture

                var path = oObjList[i1].ObjDef().Attribute(9, nloc).GetValue(false); --> get the correct url link


                //Java File to get the picture

                var fileMyFile = new; --> Convert to system path



                var reader = new;

                var fileByteArray = [];

                //Convert picture to ByteArray

                fileByteArray = java.nio.file.Files.readAllBytes(fileMyFile.toPath());


                //Create JavaScript Array

                var javaScriptArray = new Array();


                //Now push data from Java Array to JavaScript Array

                for (var i = 0; i < fileByteArray.length; i++){




                //Create Image from data

                var image = Context.createPicture(javaScriptArray, Constants.IMAGE_FORMAT_JPG);




                //----------------------------Read Image from Attribute----------------------------------

Thank you for helping me out :)

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by Torsten Haase
Posted on Thu, 10/22/2020 - 14:10

Hi Gabor,

your picture is not a file on your file system but requires a HTTP connection. See the sample script below how to insert a picture from the web into an ARIS report:

var output = Context.createOutputObject()

var obj = ArisData.getSelectedObjDefs()[0]
var attr = obj.Attribute(Constants.AT_DESC, Context.getSelectedLanguage())
if(attr.IsMaintained()) {
    var sVal = attr.getValue()
    var url = new;
    var conn = url.openConnection();
    var byteArray = conn.getInputStream().readAllBytes()
    var picture = Context.createPicture ( byteArray, "jpg" ) //or "png" ...
    output.OutGraphic (picture, 100, 210, 297)


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